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CONGENTRATION OF STOCK SOLUTIONS: (M, mollh) YOU MUST SHOW ALL CALCULATIONS TO RECEIVE CREDI FOR THEMI Calculations:
PART I. AND II. Room temperature 22∘C. Temperature of reaction solution 8∘C.
ORDER OF REACTION WTH RESPECT TO THE REACTANTS: \begin{tabular}{|c|l|} \hline ORDERWITH RESPECT TO & \\ \hline H2O2 & ORDER \\ \hline (compare flasks #1 and #2 ) & \\ \hlineI∗ & 1 order \\ \hline (Compare flasks #1 and #4) & \\ \hlineH+ \\ (compare flasks #1 and #5 ) & \\ \hline Overall order of the reaction & \\ \hline \end{tabular} YOU MUST SHOW ALL CALCULATIONS TO RECENE CREDT FOR THEMI Calculations: H2O2→(5.33×10−2M/2.67×10−2M)x=5.43×10−4M per min/2.59×10−4M per −2min→2x=21→x=1 I∗→(2.33×10−2M/1.17×10−2M)y=1.0×10−3M per min/5.43×10−4M per min→2y= 21→y=1 H+→(3.52×10−5M/1.76×10−5M)z=5.70×10−4M per min/5.43×10−4M per min →2z= 1→z=0.5 Overall order of the reaction →1+1+0.5=2.5 order
YOU MUST SHOW ALL CALCULATIONS TO RECENE CREDI FOR THEMI Calculations: DISCUSSION AND CONCLUSIONS SECTION:
\begin{tabular}{|c|c|c|c|c|c|c|c|} \hline Flask No. & KI (mL) & Starch (mL) & DI water (mL) & Buffer (mL) & Acid (mL) & Na2 S2O3 ( mL) & H2O2( mL) \\ \hline 1 & 1.75 & 2.50 & 48.25 & 15.00 & 0 & 2.50 & 5.00 \\ \hline 2 & 1.75 & 2.50 & 50.75 & 15.00 & 0 & 2.50 & 2.50 \\ \hline 3 & 3.50 & 2.50 & 46.50 & 15.00 & 0 & 2.50 & 5.00 \\ \hline 4 & 3.50 & 2.50 & 46.50 & 15.00 & 0 & 2.50 & 5.00 \\ \hline 5 & 1.75 & 2.50 & 23.25 & 15.00 & 25.0 & 2.50 & 5.00 \\ \hline 1+Cu2+ & 1.75 & 2.50 & 48.25 & 15.00 & 0 & 2.50 & 5.00 \\ \hline \end{tabular}