1. In a vinegar analysis lab. 5.0 mL of vinegar (mass =4.97 g) was obtained from a bottle that read 5.0% acidity. During

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1 In A Vinegar Analysis Lab 5 0 Ml Of Vinegar Mass 4 97 G Was Obtained From A Bottle That Read 5 0 Acidity During 1 (21.92 KiB) Viewed 39 times

1. In a vinegar analysis lab. 5.0 mL of vinegar (mass =4.97 g) was obtained from a bottle that read 5.0% acidity. During a typical titration reaction, it was determined that the vinegar required 36.25 mL of 0.10MNaOH to reach the endpoint (Note: the initial reading is 0.00 mL and the final reading is 36.25 mL.). HAC+NaOH→NaAC+H2​O a) Calculate the \% acetic acid by weight. (MM acetic acid =60 g/mol ) b) Calculate the accuracy of vinegar analysis (Assume the true value is 5.00% )