Combining 0.309 molFeF2 with excess carbon produced 11.5 g Fe. Fe2O3+3C⟶2Fe+3CO What is the actual yield of iron in m
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Combining 0.309 molFeF2 with excess carbon produced 11.5 g Fe. Fe2O3+3C⟶2Fe+3CO What is the actual yield of iron in m
Combining 0.309 molFeF2 with excess carbon produced 11.5 g Fe. Fe2O3+3C⟶2Fe+3CO What is the actual yield of iron in moles? actual yield: What is the theoretical yield of iron in moles? theoretical yield: What is the percent yield?
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