Iron(II) ion is oxidized by hydrogen peroxide in acidic solution. H2​O2​(aq)+2Fe+2(aq)+2H+1(aq)→2Fe+3(aq)+2H2​O (I) ​ Th

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answerhappygod
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Iron(II) ion is oxidized by hydrogen peroxide in acidic solution. H2​O2​(aq)+2Fe+2(aq)+2H+1(aq)→2Fe+3(aq)+2H2​O (I) ​ Th

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Iron Ii Ion Is Oxidized By Hydrogen Peroxide In Acidic Solution H2 O2 Aq 2fe 2 Aq 2h 1 Aq 2fe 3 Aq 2h2 O I Th 1
Iron Ii Ion Is Oxidized By Hydrogen Peroxide In Acidic Solution H2 O2 Aq 2fe 2 Aq 2h 1 Aq 2fe 3 Aq 2h2 O I Th 1 (54 KiB) Viewed 35 times
Iron Ii Ion Is Oxidized By Hydrogen Peroxide In Acidic Solution H2 O2 Aq 2fe 2 Aq 2h 1 Aq 2fe 3 Aq 2h2 O I Th 2
Iron Ii Ion Is Oxidized By Hydrogen Peroxide In Acidic Solution H2 O2 Aq 2fe 2 Aq 2h 1 Aq 2fe 3 Aq 2h2 O I Th 2 (54 KiB) Viewed 35 times
Iron Ii Ion Is Oxidized By Hydrogen Peroxide In Acidic Solution H2 O2 Aq 2fe 2 Aq 2h 1 Aq 2fe 3 Aq 2h2 O I Th 3
Iron Ii Ion Is Oxidized By Hydrogen Peroxide In Acidic Solution H2 O2 Aq 2fe 2 Aq 2h 1 Aq 2fe 3 Aq 2h2 O I Th 3 (69.06 KiB) Viewed 35 times
Iron(II) ion is oxidized by hydrogen peroxide in acidic solution. H2​O2​(aq)+2Fe+2(aq)+2H+1(aq)→2Fe+3(aq)+2H2​O (I) ​ The rate law for this reaction is rate =k[H2​O2​] [Fe+2]. What is the order of this reaction with respect to Fe+2 ? Enter your answer as a digit, not the word.
The rate law for the reaction of nitrogen dioxide with ozone has the form  rate =k[NO2​][O3​].  How does doubling the concentration of [NO2​] affect the rate? Select one: a. The rate would double. b. The rate would not change. c. The rate would decrease by one-half. d. The rate would increase by one-fourth. e. The rate would triple.
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