(0/1 pts) Calculated [acetate]/[acetic acid]: (−1 pts) Incorrect. Use the Henderson-Hasselbalch equation, pH=pKa​+log([ 

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answerhappygod
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(0/1 pts) Calculated [acetate]/[acetic acid]: (−1 pts) Incorrect. Use the Henderson-Hasselbalch equation, pH=pKa​+log([ 

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0 1 Pts Calculated Acetate Acetic Acid 1 Pts Incorrect Use The Henderson Hasselbalch Equation Ph Pka Log 1
0 1 Pts Calculated Acetate Acetic Acid 1 Pts Incorrect Use The Henderson Hasselbalch Equation Ph Pka Log 1 (58.85 KiB) Viewed 34 times
(0/1 pts) Calculated [acetate]/[acetic acid]: (−1 pts) Incorrect. Use the Henderson-Hasselbalch equation, pH=pKa​+log([ acid ][ base ]​) with your target pH and the pKa​ of acetic acid, 4.756. Total volume of buffer prepared: 50.0 mL (0/1pts) Volume of sodium acetate used (mL) : (-1 pts) Incorrect. Set up a system of equations using the total volume of buffer prepared and the ratio of [base] to [acid] in the buffer. (1/1pts) Volume of acetic acid used (mL) :
Part IV: Buffer pH Change Target ph:5.40pH=pka​+log [aceticacid] [ Sodiumacetate] ​ 5.40=4.75+log [aceticaid] [ actate] ​ pka of acetic acid ⇒4.76 PH=5.40=4.76105.40−4.76=10−0.64=0.2290.770%​ val of [ActicAcid] 50 mL(1−0.229)=38.54 mL val of [5odivmacetate] 50 mL(0.229)=11.45 mL
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