Combustion of glucose (C6​H12​O6​) is the main source of eneray for animal cells: C6​H12​O6​( s)+6O2​(g)→6CO2​(g)+6H2​O(

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answerhappygod
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Combustion of glucose (C6​H12​O6​) is the main source of eneray for animal cells: C6​H12​O6​( s)+6O2​(g)→6CO2​(g)+6H2​O(

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Combustion Of Glucose C6 H12 O6 Is The Main Source Of Eneray For Animal Cells C6 H12 O6 S 6o2 G 6co2 G 6h2 O 1
Combustion Of Glucose C6 H12 O6 Is The Main Source Of Eneray For Animal Cells C6 H12 O6 S 6o2 G 6co2 G 6h2 O 1 (27.07 KiB) Viewed 42 times
Combustion of glucose (C6​H12​O6​) is the main source of eneray for animal cells: C6​H12​O6​( s)+6O2​(g)→6CO2​(g)+6H2​O(l)ΔGr×m​(37∘C)=−2872 kJ This energy is generally stored as ATP (adenosine triphosphate) molecules, which can release it when comenient by hydrolysis ("water assisted . decomposition") into ADP (adenosine diphosphate) molecules and a phosphate anion, often given the symbol P1​ in biochemistry? ATP(aq)→ADP(aq)+Pi​(aq)ΔGrx ​=−35 to 70 kJ The actual amount of free energy released by the hydrolysls of ATP varies, depending on the exact conditions inside the cell. Suppose under certalin conditions hydrolysis of ATP actually releases −63.3 kJ/mol. Calculate the maximum number of ATPs that could be created frorn ADPs and Pf ​ by the combustion of a molecule of glucose. Your answer must be a whole number.
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