ares of toone 4 X 1.25×10−12 s the half-life of 14C is 5730y. Additionally, 1 mol =6.622×1023 partictes. 1y=365.25 days,

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answerhappygod
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ares of toone 4 X 1.25×10−12 s the half-life of 14C is 5730y. Additionally, 1 mol =6.622×1023 partictes. 1y=365.25 days,

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Ares Of Toone 4 X 1 25 10 12 S The Half Life Of 14c Is 5730y Additionally 1 Mol 6 622 1023 Partictes 1y 365 25 Days 1
Ares Of Toone 4 X 1 25 10 12 S The Half Life Of 14c Is 5730y Additionally 1 Mol 6 622 1023 Partictes 1y 365 25 Days 1 (12.43 KiB) Viewed 38 times
An archaeologist finds some ancient jewelry made from bone. The jewelry has a carbon mass of 254 g (HINT: Assume all the carbon is 12C and determine the number of atoms, 12C has a molar mass of 12 g/mol) and careful measurements show that the remaining 14C has a current decay rate of 16 decays/s. Determine the age of the bone (and presumably the jewelry). The ratio of 14C to 12C when the animal died was 1.25×10-12 & the half-life of 14C is 5730 y. Additionally, 1 mol = 6.022×1023 particles, 1 y = 365.25 days, & 1 day = 24 h.
age of bone = 14958.65 y
Incorrect: Your answer is incorrect.
Ares Of Toone 4 X 1 25 10 12 S The Half Life Of 14c Is 5730y Additionally 1 Mol 6 622 1023 Partictes 1y 365 25 Days 2
Ares Of Toone 4 X 1 25 10 12 S The Half Life Of 14c Is 5730y Additionally 1 Mol 6 622 1023 Partictes 1y 365 25 Days 2 (8.98 KiB) Viewed 38 times
ares of toone 4 X
1.25×10−12 s the half-life of 14C is 5730y. Additionally, 1 mol =6.622×1023 partictes. 1y=365.25 days, 8 day =24 h. age of berie = X
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