(1 point) Let f(x,y)=6x2y4. Then fx(x,y)=fx(3,y)=fx(x,−2)=fx(3,−2)=fy(x,y)=fy(3,y)=fy(x,−2)=fy(3,−2)=
1 point) Calculate all four second-order partial derivatives and check that fxy=fyz : Assume the variables are restricted to a domain on which the functon is lefined. f(x,y)=e3xy fzz= fyy= fzy= fyz=
(1 point) Let f(x,y)=6x2y4. Then fx(x,y)=fx(3,y)=fx(x,−2)=fx(3,−2)=fy(x,y)=fy(3,y)=fy(x,−2)=fy(3,−2)= 1 point)
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(1 point) Let f(x,y)=6x2y4. Then fx(x,y)=fx(3,y)=fx(x,−2)=fx(3,−2)=fy(x,y)=fy(3,y)=fy(x,−2)=fy(3,−2)= 1 point)
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