Consider the differentiation problem dxd​[5⋅cotx]. First, we can pull out the constant 5 , using the constant multiple r

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Consider the differentiation problem dxd​[5⋅cotx]. First, we can pull out the constant 5 , using the constant multiple r

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Consider The Differentiation Problem Dxd 5 Cotx First We Can Pull Out The Constant 5 Using The Constant Multiple R 1
Consider The Differentiation Problem Dxd 5 Cotx First We Can Pull Out The Constant 5 Using The Constant Multiple R 1 (38.25 KiB) Viewed 31 times
Consider the differentiation problem dxd​[5⋅cotx]. First, we can pull out the constant 5 , using the constant multiple rule. 5⋅dxd​[cotx] Then, we can apply the differentiation formula we've learned for cotx. - 5⋅(−csc2x) Depending on what happens next (we could continue with the next steps of a word problem, or compare answers with a classmate, etc.), we might want a different format for this answer. Which of the following is also an equivalent expression for dxd​[5⋅cotx] ? tan2x1​ 5+5⋅cot2x −5(1+cot2x) 5⋅cscx
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