k=1∑∞(9k1−9k+21) k=1∑∞(1+k4)5k k=1∑∞k2+4k+31
-
answerhappygod
- Site Admin
- Posts: 899604
- Joined: Mon Aug 02, 2021 8:13 am
k=1∑∞(9k1−9k+21) k=1∑∞(1+k4)5k k=1∑∞k2+4k+31
k=1∑∞(9k1−9k+21) k=1∑∞(1+k4)5k k=1∑∞k2+4k+31
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!