y=1−x4​+x2sin−1x2(k)y=(3t2+13t2−1​)−3 (i) y=xx+1​

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answerhappygod
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y=1−x4​+x2sin−1x2(k)y=(3t2+13t2−1​)−3 (i) y=xx+1​

Post by answerhappygod »

Y 1 X4 X2sin 1x2 K Y 3t2 13t2 1 3 I Y Xx 1 1
Y 1 X4 X2sin 1x2 K Y 3t2 13t2 1 3 I Y Xx 1 1 (30.59 KiB) Viewed 33 times
Y 1 X4 X2sin 1x2 K Y 3t2 13t2 1 3 I Y Xx 1 2
Y 1 X4 X2sin 1x2 K Y 3t2 13t2 1 3 I Y Xx 1 2 (30.59 KiB) Viewed 33 times
y=1−x4​+x2sin−1x2(k)y=(3t2+13t2−1​)−3 (i) y=xx+1​
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