Find f′(x) and find the equation of the line tangent to the graph of f at the indicated value of x. f(x)=x3(3−x)3⋅x=1 f′
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Find f′(x) and find the equation of the line tangent to the graph of f at the indicated value of x. f(x)=x3(3−x)3⋅x=1 f′
Find f′(x) and find the equation of the line tangent to the graph of f at the indicated value of x. f(x)=x3(3−x)3⋅x=1 f′(x)= The equation of the line tangent to the graph of fatx=1 is y=
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