9. Shifting the Center. When the function f(x)=1/(1−x) is expanded as a power series with center a=0 we get the usual ge
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9. Shifting the Center. When the function f(x)=1/(1−x) is expanded as a power series with center a=0 we get the usual ge
9. Shifting the Center. When the function f(x)=1/(1−x) is expanded as a power series with center a=0 we get the usual geometric series 1−x1=n=0∑∞xn−1<x<1 Use the fact that 1−x=2−(x+1) to expand f as a power series centered at a=−1 : 1−x1=n=0∑∞cn(x+1)n What is the new interval of convergence?
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