- 1 6x3 4x X 1 Dx 2 4ex 2x Dx 3 9t3t2 7 Dt 4 Ln T 5t Dt A T1 Dt B 4ex 2xln 2 C C 25t2 T1 1 (38.01 KiB) Viewed 37 times
(1.) ∫(6x3−4x+x−1)dx (2.) ∫(4ex+2x)dx (3.) ∫(9t3t2+7)dt (4.) ∫(ln(t)5t)dt (a.) ∫t1dt (b.) 4ex+2xln(2)+C (c.) 25t2t1
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answerhappygod
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(1.) ∫(6x3−4x+x−1)dx (2.) ∫(4ex+2x)dx (3.) ∫(9t3t2+7)dt (4.) ∫(ln(t)5t)dt (a.) ∫t1dt (b.) 4ex+2xln(2)+C (c.) 25t2t1
(1.) ∫(6x3−4x+x−1)dx (2.) ∫(4ex+2x)dx (3.) ∫(9t3t2+7)dt (4.) ∫(ln(t)5t)dt (a.) ∫t1dt (b.) 4ex+2xln(2)+C (c.) 25t2t1+C (d.) 23x4−2x2+ln∣x∣+C (e.) 5ln∣lnt∣+C (f.) 69(3t2+7)23+C (g.) (3t2+7)23+C
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