Find the volume of the solid that lies under the paraboloid z=4x2+4y2, above the xy-plane, and inside the cylinder x2+y2
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Find the volume of the solid that lies under the paraboloid z=4x2+4y2, above the xy-plane, and inside the cylinder x2+y2
Find the volume of the solid that lies under the paraboloid z=4x2+4y2, above the xy-plane, and inside the cylinder x2+y2=2x. Solution The solid lies above the disk D whose boundary circle has equation x2+y2=2x or, after completing the square, (x−)2+y2= In polar coordinates we have x2+y2=r2 and x=rcos(θ), so the boundary circle becomes r2=2rcos(θ), or r=2 cos (θ). Thus the disk D is given by D={(r,θ)∣−π/2≤θ≤π/2,0≤r≤2cos(θ)} and, by this formula, we have the following. V=∬D(4x2+4y2)dA =∫−π/2π/2∫02cos(θ)(1)rdrdθ =∫−π/2π/2[]02cos(θ)dθ =∫0π/2cos4(θ)dθ =∫0π/2(21+cos(2θ))2dθ =∫0π/2[1+2cos(2θ)+21(1+cos(4θ))]dθ
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