(b(t)⋅c(t))′=b′(t)⋅c(t)+b(t)⋅c′(t
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answerhappygod
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(b(t)⋅c(t))′=b′(t)⋅c(t)+b(t)⋅c′(t
(b(t)⋅c(t))′=b′(t)⋅c(t)+b(t)⋅c′(t
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