- Give The Solution Of 9 11 I Need The Solution At 11 00 Pm Thank You 1 (109.95 KiB) Viewed 29 times
Give the solution of 9-11, I need the solution at 11:00 pm. Thank you
-
answerhappygod
- Site Admin
- Posts: 899604
- Joined: Mon Aug 02, 2021 8:13 am
Give the solution of 9-11, I need the solution at 11:00 pm. Thank you
Give the solution of 9-11, I need the solution at 11:00 pm.Thank you
CALCULUS 1: ASSIGNMENT NO. 4 9. y=(sinx)cosx Answer: y′=(sinx)cosx−1[cos2x−sin2xln(sinx)] 10. y=(cos−1x)lnx2 Answer: y′=(cos−1x)lnx2−1[x1−x2−xlnx2+ln(cos−1x)(cos−1x)2(1−x2)] 11. y=(sinhx)cosx Answer: (sinhx)cosx−1[(cosxcoshx−sinxsinhxln(sinhx)] 12. y=x8(x+2)6(x+1)2(x−1)4 Answer: y′=x8(x+2)6(x+1)2(x−1)4[x+12+x−14−x8−x+26] y′=x9(x+2)7−2(x+1)(x−1)3[4x3+x2+9x−8]
CALCULUS 1: ASSIGNMENT NO. 4 9. y=(sinx)cosx Answer: y′=(sinx)cosx−1[cos2x−sin2xln(sinx)] 10. y=(cos−1x)lnx2 Answer: y′=(cos−1x)lnx2−1[x1−x2−xlnx2+ln(cos−1x)(cos−1x)2(1−x2)] 11. y=(sinhx)cosx Answer: (sinhx)cosx−1[(cosxcoshx−sinxsinhxln(sinhx)] 12. y=x8(x+2)6(x+1)2(x−1)4 Answer: y′=x8(x+2)6(x+1)2(x−1)4[x+12+x−14−x8−x+26] y′=x9(x+2)7−2(x+1)(x−1)3[4x3+x2+9x−8]
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!