Calculus III
(1 point) Let f(x,y)=(−(4x+y))9. Then ∂x∂y∂2f=∂x∂y∂x∂3f=∂x2∂y∂3f=
(1 point) Let f(x,y)=(−(4x+y))9. Then ∂x∂y∂2f=∂x∂y∂x∂3f=∂x2∂y∂3f=
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(1 point) Let f(x,y)=(−(4x+y))9. Then ∂x∂y∂2f=∂x∂y∂x∂3f=∂x2∂y∂3f=
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