- 1 (15.1 KiB) Viewed 42 times
Given that sinθ=1715 with θ in quadrant II, what is sin2θ ? 289161 none of these 289−161 289−∠4U 289240
-
answerhappygod
- Site Admin
- Posts: 899604
- Joined: Mon Aug 02, 2021 8:13 am
Given that sinθ=1715 with θ in quadrant II, what is sin2θ ? 289161 none of these 289−161 289−∠4U 289240
Given that sinθ=1715 with θ in quadrant II, what is sin2θ ? 289161 none of these 289−161 289−∠4U 289240
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!