A=[1224] Recall that row(A) and nul (A) are orthogonal complements. So we can split any x∈R2 into a unique component x

Post by **answerhappygod** » Thu Jul 14, 2022 3:56 pm

: A 12 24 Recall That Row A And Nul A Are Orthogonal Complements So We Can Split Any X R2 Into A Unique Component X 1 (37.03 KiB) Viewed 32 times

A=[1224] Recall that row(A) and nul (A) are orthogonal complements. So we can split any x∈R2 into a unique component xr in row (A) and a unique component xn in nul (A) such that x=xr+xn= PART A) Give a basis for row (A) and nul (A) is Prow (A)+Pneal (A) ? PART C) Let x=(0,3). Compute xr and xn using your answers from part b. PART D) Provide a sketch which displays row (A), nul (A), and the x,xr and xn from part c. PART E) | xr∥ measures the shortest distance from to (Fall in the blanks so that the statement is true. No explanation reeded.).

A=[12​24​] Recall that row(A) and nul (A) are orthogonal complements. So we can split any x∈R2 into a unique component x

A=[12​24​] Recall that row(A) and nul (A) are orthogonal complements. So we can split any x∈R2 into a unique component x

A=[1224] Recall that row(A) and nul (A) are orthogonal complements. So we can split any x∈R2 into a unique component x

A=[1224] Recall that row(A) and nul (A) are orthogonal complements. So we can split any x∈R2 into a unique component x