Part A: A particle is moving along a straight line with a velocity v(t)=(2t2−5t+8)sm​ where t is in seconds. It is known

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Part A A Particle Is Moving Along A Straight Line With A Velocity V T 2t2 5t 8 Sm Where T Is In Seconds It Is Known 1 (39.07 KiB) Viewed 36 times

Part A: A particle is moving along a straight line with a velocity v(t)=(2t2−5t+8)sm​ where t is in seconds. It is known that the particle has a position of 20 m when t=0. - Determine the acceleration of the particle at t=2 s. - Determine the location of the particle when t=1 s. Part B: Instead of the information provided in Part A, you are told that the particle has an acceleration described by the equation a(s)=(2s−5)s2m​ where s is in meters. If the particle starts from rest at the original position of s=0, determine the following: - The position at which the particle's velocity returns to zero. - If the particle changes direction at the point where its velocity is zero, determine the velocity of the particle when it has travelled a total distance of 7 m.