- Q Mass Hanging From Two Strings In The Limit Abokimark This Page Consider The Free Body Diagram Fbd Analysis Of A Mas 1 (18.26 KiB) Viewed 38 times
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0.0H0.0 points (graded) Draw the FBD's for the hanging mass and consider what happens as the angle θ1 takes various limits while the angle θ2 is constrained by θ2=πrad−θ1. Select the correct statements. As the angle θ1 increases from zero the angle θ2 increases from zero. As the angle θ1 increases from zero the angle θ2 decreases from π/2rad. As the angle θ1 increases from zero the angle θ2 decreases from n rad. The tension in the rope which has angle θ1 is less than the tension in the rope which has angle θ2. The tension in the rope which has angle θ1 is equal to the tension in the rope which has angle θ2. The tension in the rope which has angle θ1 is greater than the tension in the rope which has angle θ2. As the angle θ1 increases from zero the tension in the rope at angle θ1 increases from zero. As the angie θ1 increases from zero the tension in the rope at angle θ1 increases from a non-zero value. As the angle θj increases from zero the tension in the rope at angle θ1 decreases from a non-zero value. As the angle θ1 increases from zero the tension in the rope at angle θ1 decreases from infinity.
Consider the Free Body Diagram (FBD) analysis of a block of mass m>0, sliding in the direction shown on a ramp having coefficlent of kinet friction μ and angle θ to the horizontal, in gravity of acceleration g. Let FN be the magnitude of the normal force, and let FD be the downhil component of the body force. The goal is to calculate the acceleration of the block. Gravity and Friction 0.0/10.0 points (graded) Draw the FBD for the block and use it to calculate the acceleration of the block. Select the correct statements. When FD>μFN the block's speed is increasing. When FD>μFN the block's speed is decreasing. When FD<μFN the blocks speed is increasing. When FD<μFN the block's speed is decreasing When FD>μFN the magnitude of the total force on the block is FD−μFN. When FD>μFN the magnitude of the fotal force on the block is FD+μFN - When FD<μFN the magnitude of the total force on the block is μFN−FD. When FD<μFN the magnitude of the total force on the block is μFN+FD.