Modify the following MATLAB code to get a triangle. Take a screenshot of the result. FUNCTION TESTBENCH function [xa,xd,

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Modify the following MATLAB code to get atriangle. Take a screenshot of the result.
FUNCTION
TESTBENCH
function [xa,xd,ya,yd]=Lab7(mode)
T=0.1;
f=1/T;
dt=0.001;
dt1=0.01;
t=0:dt:1-dt;
t1=0:dt:1-dt1;
%xa=square(2*pi*f*t); Analog signal
xa=repmat([ones(1,50) -1*ones(1,50)],1,10);
%xd=square(2*pi*f*t1); Digital signal
xd=repmat([ones(1,5) -1*ones(1,5)],1,10);
ya=zeros(1,1024);
yd=zeros(1,1024);
switch mode
case 0 %Periodic signal
%FFT of analog (FS)
ya=abs(fftshift(dt*fft(xa(1:0.1*length(xa)),128)));
%FFT od discrete (DFT)
yd=abs(fftshift(dt1*fft(xd(1:0.1*length(xd)),128)));
type1='FS';
type2='DFT';
case 1
%FFT of analog (CTFT)
xa=[xa(1:0.1*length(xa)) zeros(1,0.9*length(xa))];
%FFT of digital (DTFT)
yd=[xa(1:0.1*length(xd)) zeros(1,0.9*length(xd))];
ya=abs(fftshift(dt*fft(xa,1024)));
yd=abs(fftshift(dt1*fft(xd,1024)));
type1='CTFT';
type2='DTFT';
end
yd=repmat(yd,1,9);
f1=-1/(2*dt):1/(length(ya)*dt):1/(2*dt);
f2=-1/(2*dt1):1/(length(yd)*dt):1/(2*dt1);
clear; close all; clc;
dt=0.001;
dt1=0.01;
mode=1; %0:Periodic signal, 1:Aperiodic signal
[xa,xd,ya,yd]=Lab7(mode);
f1=-1/(2*dt):1/(length(ya)*dt):1/(2*dt);
f2=-1/(2*dt1):1/(length(yd)*dt1):1/(2*dt1);
ta=linspace(0,1,length(xa));
td=linspace(0,1,length(xd));
%Verification
subplot(2,2,1)
plot(ta,xa,'.’); grid on;
title('Analog Signal')
ylabel('Amplitude')
subplot(2,2,2)
plot(td,xd,'.');grid on;
title('Discrete Signal')
ylabel('Amplitude')
subplot(2,2,3)
plot(f1(1:end-1),ya); grid on;
title('FS/CTFT')
ylabel('Amplitude')
subplot(2,2,4)
plot(f2(1:end-1),yd); grid on;
title('DFT/DTFT')
ylabel('Amplitude')