Problem 2: Table 12.2 in the textbook by Harris lists the properties of some commonly produced hadrons. You can also fin

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Problem 2: Table 12.2 in the textbook by Harris lists the properties of some commonly produced hadrons. You can also fin

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Problem 2 Table 12 2 In The Textbook By Harris Lists The Properties Of Some Commonly Produced Hadrons You Can Also Fin 1
Problem 2 Table 12 2 In The Textbook By Harris Lists The Properties Of Some Commonly Produced Hadrons You Can Also Fin 1 (124.12 KiB) Viewed 40 times
Problem 2: Table 12.2 in the textbook by Harris lists the properties of some commonly produced hadrons. You can also find such a table online: http://hyperphysics.phy-astr.gsu.edu/hb ... aryon.html http://hyperphysics.phy-astr.gsu.edu/hb ... meson.html Part (a). Each of the following decays violates at least one "rule” corresponding to a conservation law. Identify at least one broken conservation law for each decay: It →etty Aº +p+K 1° +1° + + ť → éty Part (b). The following decay might appear to be allowed, but it is not allowed. Can you explain why? Aº + T+7 Part (c). A tau lepton may decay into a regular electron plus other particles. What other particles must be produced? Write down the Feynman diagram that describes this decay. Part (d). Write down the Feynman Diagrams for the following decays: Ω- + Ξυ + π Kº +++ + at ut tvu Part (e). Assume that the following collision interaction is governed by the strong nuclear force between quarks. Write down a plausible Feynman diagram for this interaction. p+on+ñ Part (f) A A++ is unusual in that it is a baryon with a charge of twice that of the proton. It is made of three “up” quarks. Each up quark has the same charge, spin, etc. Of course we can assign one of these up quark a z-component to the spin of “up” and a second quark “down” – allowing for two quarks out of three of the confined to the bound state. But in this case we see three quarks. So we have a problem in that we cannot put three identical quarks into this baryon unless at least two of them have the same spin state. Explain how and why having what appears to be "three identical quarks" in the same baryonic bound state does not violate the Exclusion Principle?
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