The lower end of the thin uniform rod in (Figure 1) is attached to the floor by a frictionless hinge at point P. The rod

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The lower end of the thin uniform rod in (Figure 1) is attached to the floor by a frictionless hinge at point P. The rod

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The Lower End Of The Thin Uniform Rod In Figure 1 Is Attached To The Floor By A Frictionless Hinge At Point P The Rod 1
The Lower End Of The Thin Uniform Rod In Figure 1 Is Attached To The Floor By A Frictionless Hinge At Point P The Rod 1 (60.8 KiB) Viewed 43 times
The Lower End Of The Thin Uniform Rod In Figure 1 Is Attached To The Floor By A Frictionless Hinge At Point P The Rod 2
The Lower End Of The Thin Uniform Rod In Figure 1 Is Attached To The Floor By A Frictionless Hinge At Point P The Rod 2 (16.04 KiB) Viewed 43 times
The lower end of the thin uniform rod in (Figure 1) is attached to the floor by a frictionless hinge at point P. The rod has mass 0.0860 kg and length 20.0 cm and is in a uniform magnetic field 0.160 T that is directed into the page. The rod is held at an angle 60.0° above the horizontal by a horizontal string that connects the top of the rod to the wall. The rod carries a current 12.0 A in the direction toward P. Figure 1 of 1 - Х X Х XB Х + Pr Х + 07 Х pl x X Х Х
Part A Calculate the tension in the string. Use the fact that IBL for a uniform bar of length L carring a current I in a magnetic field B. Express your answer with the appropriate units. μΑ ? T = 0.54 N Submit Previous Answers Request Answer X Incorrect; Try Again; 2 attempts remaining
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