The correct relation between the emitter current Ie and the base current Ib is given by

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answerhappygod
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The correct relation between the emitter current Ie and the base current Ib is given by

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a) Ib = (1 + α) Ie
b) Ib = (α – 1) Ie
c) Ie = (1 – ß) Ib
d) Ie = (1 + ß) Ib
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