Given f(x) = 2x1-10, the positive x-value that gives the smallest value of y = 6), to the nearest hundredth, is Answer:
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Given f(x) = 2x1-10, the positive x-value that gives the smallest value of y = 6), to the nearest hundredth, is Answer:
Given f(x) = 2x1-10, the positive x-value that gives the smallest value of y = 6), to the nearest hundredth, is Answer: Ruth solved the equation 8 = x-*-6 as follows. ol B x-dx-5 B-X = -*-6 x-B = √x-5 x-16% +54 = x-6 x2 - 17x + 70 = 0 6-7)-10) = 0 X = 7.10 The extraneous root(s) introduced by Ruth is/are Select one: O no extraneous root was introduced Ob. 10 c. 7 d. 7 and 10
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