Prot 0 50 KN en 0.75 m E = 100 GPa A = 18 x 104 m2 k = 1000 kN/m 2 0.75 m 3 Figure P3-7 Steel 2 Aluminum 3 40 KN 3 E = 2

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answerhappygod
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Prot 0 50 KN en 0.75 m E = 100 GPa A = 18 x 104 m2 k = 1000 kN/m 2 0.75 m 3 Figure P3-7 Steel 2 Aluminum 3 40 KN 3 E = 2

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Prot 0 50 Kn En 0 75 M E 100 Gpa A 18 X 104 M2 K 1000 Kn M 2 0 75 M 3 Figure P3 7 Steel 2 Aluminum 3 40 Kn 3 E 2 1
Prot 0 50 Kn En 0 75 M E 100 Gpa A 18 X 104 M2 K 1000 Kn M 2 0 75 M 3 Figure P3 7 Steel 2 Aluminum 3 40 Kn 3 E 2 1 (61.98 KiB) Viewed 37 times
for the bar assemblages shown in Figure P3-7 to Figure P3-9 determine the nodal displacements,the forces in each element, and the reaction. Use the direction stiffness method for these problems.
Prot 0 50 KN en 0.75 m E = 100 GPa A = 18 x 104 m2 k = 1000 kN/m 2 0.75 m 3 Figure P3-7 Steel 2 Aluminum 3 40 KN 3 E = 200 GPa A = 4 x 10-4 m2 E = 70 GP A, 2. 10m 1 m Figure P3-8 0 5kN 2. © 20 2 m
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