Q6(0) An athlete makes a vertical jump on a force platform which has been normalized for weight (i.e. the force is zero

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Q6(0) An athlete makes a vertical jump on a force platform which has been normalized for weight (i.e. the force is zero

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Q6 0 An Athlete Makes A Vertical Jump On A Force Platform Which Has Been Normalized For Weight I E The Force Is Zero 1
Q6 0 An Athlete Makes A Vertical Jump On A Force Platform Which Has Been Normalized For Weight I E The Force Is Zero 1 (55.94 KiB) Viewed 42 times
Q6(0) An athlete makes a vertical jump on a force platform which has been normalized for weight (i.e. the force is zero when the athlete is standing still on the platform) as shown in Figure 6.1. At1 = 0.3 s, At2 = 0.4s, At3 = 0.4s. F (kN) Calculate: LANDING 1.2-14 (i) The take-off velocity of the athlete. [4 Marks] (ii) The height of the jump. [4 Marks] (iii) The landing velocity of the athlete. [4 Marks] t 1.0- 0.8 TAKEOFF 0.6 F 0.4 A Atz 0.2 0.0 TI -0.2 Ati -0.4 A, -0.6 -0.8 - F2 -1.0 - AIRBORNE -1.2- Ats Figure 6.1
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