(1 - y) P=6 MPa T = 540°C Turbine 1,82% Steam generator (1) W, P2 = 500 kPa P: = 60 kPa 8.80 Consider a cogeneration sys

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answerhappygod
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(1 - y) P=6 MPa T = 540°C Turbine 1,82% Steam generator (1) W, P2 = 500 kPa P: = 60 kPa 8.80 Consider a cogeneration sys

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1 Y P 6 Mpa T 540 C Turbine 1 82 Steam Generator 1 W P2 500 Kpa P 60 Kpa 8 80 Consider A Cogeneration Sys 1
1 Y P 6 Mpa T 540 C Turbine 1 82 Steam Generator 1 W P2 500 Kpa P 60 Kpa 8 80 Consider A Cogeneration Sys 1 (209.31 KiB) Viewed 40 times
Can you solve this problem by writing a MATLAB code
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Thank you in advance
(1 - y) P=6 MPa T = 540°C Turbine 1,82% Steam generator (1) W, P2 = 500 kPa P: = 60 kPa 8.80 Consider a cogeneration system operating as shown in Fig. P8.80. Steam enters the first turbine stage at 6 MPa, 540°C. Between the first and second stages, 45% of the steam is extracted at 500 kPa and diverted to a process heating load of 5 x 108 kJ/h. Condensate exits the process heat exchanger at 450 kPa with specific enthalpy of 589.13 kJ/kg and is mixed with liquid exiting the lower-pressure pump at 450 kPa. The entire flow is then pumped to the steam generator pressure. At the inlet to the steam generator the specific enthalpy is 469.91 kJ/kg. Saturated liquid at 60 kPa leaves the condenser. The turbine stages and the pumps operate with isentropic efficiencies of 82% and 88%, respectively. Determine (a) the mass flow rate of steam entering the first turbine stage, in kg/s. (b) the net power developed by the cycle, in MW. (c) the rate of entropy production in the turbine, in kW/K. P = P1 = 6 MPa h = 469.91 kJ/kg w out Condenser Pump 2 PG=Ps = 450 kPa Pump I (1 - y) 5 -4 PA=P3 = 60 kPa *4 = 0 (saturated liquid) 77,2 = 88% ni = 88% W Heat exchanger process = 5 x 108 kJ/h Pg = 450 kPa 8 Hg = 589.13 kJ/kg
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