20. Consider the nonhomogeneous linear equation dy dt +2y = 312 + 2t - 1. In order to find the general solution, we must
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20. Consider the nonhomogeneous linear equation dy dt +2y = 312 + 2t - 1. In order to find the general solution, we must
20. Consider the nonhomogeneous linear equation dy dt +2y = 312 + 2t - 1. In order to find the general solution, we must guess a particular solution yp(t). Since the right-hand side is a quadratic polynomial, it is reasonable to guess a quadratic for Yp(1), so let yp(t) = at+ bt+c, where a, b, and c are constants. Determine values for these constants so that yp(t) is a solution. In Exercises 21-24, find the general solution and the solution that satisfies the initial condition y(0) = 0. dy 22. +y=1" + sin 31 dt
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