Figure 2 Shows A 6 Bus Power System With Two Synchronous Generators The Power System Need To Be Simulated Before Its Ac 1 (92.69 KiB) Viewed 59 times
Figure 2 Shows A 6 Bus Power System With Two Synchronous Generators The Power System Need To Be Simulated Before Its Ac 2 (64.48 KiB) Viewed 59 times
Figure 2 shows a 6-Bus power system with two synchronous generators. The power system need to be simulated before its actual implementation. Bus 1 and Bus 6 are equipped with circuit breaker CB1 and CB2, respectively. Initially, CB1 is in OPEN position, and CB2 is in CLOSE position. The power system parameters are given in Table 1. The initial voltage for all buses are 1.0 p.u. Use Sbase equals to 100 MVA. Assume CB1 and CB2 are pure conductor with zero impedance Bus 2 Bus 6(a) Bus 1(a) 1 Мтз д Bus 3 Line 1 or Line 3 Line 2 T1 Η τ4 Δ CB2 CB1 Y G2 Line 4 Line 5 - T2 T5 Bus 1(b) Bus 4 Bus 5 Bus 6(b) CB OPEN CB CLOSE Figure 2: 6-Bus Power System Table 1: Power System Component and Parameter Component Parameter Generator G1 Generator G2 20 MVA, x2 = 0.05 p.u Xº = 0.015 p.u 10 MVA x12=0.03 p.u Xº = 0.009 p.u 15 MVA, 33/132 kV X12=0.03 p.u Xº = 0.009 p.u Transformer Tl & T2
Transformer T3 & 14 15 MVA, 132/11 kV X12=0.09 p.u Xº = 0.012 p.u 10 MVA, 132/11 kV X12=0.055 p.u Xº = 0.025 p.u Transformer T5 = Line 1, Line 2 & Line 4 X0,1,2 = 0.35 p.u Line 3 & Line 5 X0.1,2 = 0.45 p.u (a) Draw the positive, negative and zero sequence equivalent circuit of Figure 1. Show all reactance values in the equivalent circuits. 15 Marks (b) CB1 is switched to CLOSE position, and CB2 is switched to OPEN position. Then, a line-to-line fault is simulated at Bus 3, between Phase A and Phase B. At zero fault impedance calculate the resulting fault current of the said bus. [12 Marks (c) Based on part (b), determine phase voltages of Bus 3 (VA, V3 and Vc). [8 Marks
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