T=T = 1045 Lly = 1345 cm V - 5 Ho = 458 cm/V-s n = 1.5x100cm = T= 300 K SOP

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answerhappygod
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T=T = 1045 Lly = 1345 cm V - 5 Ho = 458 cm/V-s n = 1.5x100cm = T= 300 K SOP

Post by answerhappygod »

T T 1045 Lly 1345 Cm V 5 Ho 458 Cm V S N 1 5x100cm T 300 K Sop 1
T T 1045 Lly 1345 Cm V 5 Ho 458 Cm V S N 1 5x100cm T 300 K Sop 1 (1.36 KiB) Viewed 36 times
and
T T 1045 Lly 1345 Cm V 5 Ho 458 Cm V S N 1 5x100cm T 300 K Sop 2
T T 1045 Lly 1345 Cm V 5 Ho 458 Cm V S N 1 5x100cm T 300 K Sop 2 (1.6 KiB) Viewed 36 times
(a) Find the carrier concentration no, po in thermal
equilibrium.
(b) Assuming a low level of excitation, the recombination factor
αr=?
(c) The excess carrier concentration in under steady state
condition δn,δp = ?
T T 1045 Lly 1345 Cm V 5 Ho 458 Cm V S N 1 5x100cm T 300 K Sop 3
T T 1045 Lly 1345 Cm V 5 Ho 458 Cm V S N 1 5x100cm T 300 K Sop 3 (914 Bytes) Viewed 36 times
T=T = 1045
Lly = 1345 cm V - 5
Ho = 458 cm/V-s n = 1.5x100cm = T= 300 K
SOP
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