Vcc 10 V Rc 3 9 K22 C Vo Rf 68k12 Ha C R R Figure P2 60 2 61 The Biasing Scheme Of The Ce Amplifier Of Fig P2 61 Is 1 (43.47 KiB) Viewed 37 times
Vcc 10 V Rc 3 9 K22 C Vo Rf 68k12 Ha C R R Figure P2 60 2 61 The Biasing Scheme Of The Ce Amplifier Of Fig P2 61 Is 2 (12.1 KiB) Viewed 37 times
Vcc 10 V Rc 3 9 K22 C Vo Rf 68k12 Ha C R R Figure P2 60 2 61 The Biasing Scheme Of The Ce Amplifier Of Fig P2 61 Is 3 (22.92 KiB) Viewed 37 times
Vcc (10 V) Rc 3.9 k22 C₂ Vo RF 68k12 HA C R R; FIGURE P2.60 2.61 The biasing scheme of the CE amplifier of Fig. P2.61 is similar to that of Fig. P2.60, except that Reis replaced by a current source Istas (Such a source, whose details we are omitting for simplic- ity, could be implemented with a pnp BJT, along the lines of Fig. 2.46). With this modification, the resistance seen by the collector can be made quite high, indicating that this circuit is capable of potentially high voltage gains. (a) Assuming B; = 100, VBElon) = 0.7 V, and VA = 100 V, use the BJT large-signal and small-signal models to find the de collector voltage Vc and the unloaded ac voltage gain v./v;. (6) Repeat if Igas is doubled to 2 mA. Comment on your findings.
VCC IBIAS 1 mA C2 V RF HE 100 k12 T Vi RO HH R; FIGURE P2.61
Vcc (12V) R 100 k12 W RE 10 k12 R2 10 10 w RO 100 k12 3.3 ΜΩ: V. LD 0.5 mA V. LD 10 FIGURE 2.46 Using a pnp BJT to implement a current source, and its Norton equivalent.
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