Part 1 Rigid bar ABCD is supported by a pin connection at A and by two axial bars (1) and (2). Bar (1) is a 28-in.-long

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Part 1 Rigid bar ABCD is supported by a pin connection at A and by two axial bars (1) and (2). Bar (1) is a 28-in.-long

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Part 1 Rigid Bar Abcd Is Supported By A Pin Connection At A And By Two Axial Bars 1 And 2 Bar 1 Is A 28 In Long 1
Part 1 Rigid Bar Abcd Is Supported By A Pin Connection At A And By Two Axial Bars 1 And 2 Bar 1 Is A 28 In Long 1 (377.24 KiB) Viewed 34 times
Part 1 Rigid bar ABCD is supported by a pin connection at A and by two axial bars (1) and (2). Bar (1) is a 28-in.-long bronze [E = 14600 ksi, a = 8.7 x 10-6/°F] bar with a cross-sectional area of 1.50 in.2. Bar (2) is a 46-in.-long aluminum alloy [E = 8300 ksi, a = 12 10-6/°F] bar with a cross-sectional area of 2.00 in.2. Both bars are unstressed before the load Pis applied. Assume L1=28 in., L2=46 in., a=34 in., b=52 in., and c=16 in. If a concentrated load of P = 23 kips is applied to the rigid bar at D and the temperature is decreased by 105°F, determine: (a) the normal stresses in bars (1) and (2). (b) the normal strains in bars (1) and (2). (c) the deflection of the rigid bar at point D. (2) L2 B D L1 (1) b Using a FBD of the beam, assuming members in tension, relate the force in the members and the applied force P by summing moments about the pin at A. Assume counterclockwise is positive in writing the equation. Answer: i in.) F1+( i in.) F2 + ( i in.) (23 kips) = 0. Save for Later Attempts: 0 of 3 used Submit Answer
Part 2 Assume the rigid bar ABCD rotates clockwise around point A. Using a deflection sketch, relate the deflections of points B and C. Assume positive deflections are down. Answer: Vg = i VC Save for Later Attempts: 0 of 3 used Submit Answer Part 3 Relate the deformations of member (1) and member (2). Answer: 8] = i 82 Save for Later Attempts: 0 of 3 used Submit Answer Part 4 Using the relationships for deformation in terms of force and temperature change for each member together with Eqn. (3), derive a compatibility equation for the structure. F1L1 F2L2 Answer: = + Q AT L AE + a24T2L2 A2E2 Save for Later Attempts: 0 of 3 used Submit Answer
Part 5 Solve for F2 and F1 using the results from parts 1 and 4. Answers: F1 = i kips, F2 = i kips. Save for Later Attempts: 0 of 3 used Submit Answer Part 6 Determine the normal stress in each bar. Use positive if tensile, negative if compressive. Answers: 01 = i ksi, o2 = i ksi. Save for Later Attempts: 0 of 3 used Submit Answer Part 7 Determine the normal strain in bars (1) and (2). Use positive if tensile, negative if compressive. Answers: E = με, έ2 = με. Save for Later Attempts: 0 of 3 used Submit Answer
Part 8 Determine the deflection of the rigid bar ABCD at point C. A positive deflection is down. Answer: vc= i in. Save for Later Attempts: 0 of 3 used Submit Answer Part 9 Determine the deflection of the rigid bar ABCD at point D. A positive deflection is down. Answer: Vp = in. Save for Later Attempts: 0 of 3 used Submit Answer
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