B S M Remarks 0 666 Bm Sios Rl I S M F S M Hi M Mamsl 124 122 123 456 0 570 123 552 0 634 123 488 0 681 123 1 (36.24 KiB) Viewed 25 times
B S M Remarks 0 666 Bm Sios Rl I S M F S M Hi M Mamsl 124 122 123 456 0 570 123 552 0 634 123 488 0 681 123 2 (36.24 KiB) Viewed 25 times
B S M Remarks 0 666 Bm Sios Rl I S M F S M Hi M Mamsl 124 122 123 456 0 570 123 552 0 634 123 488 0 681 123 3 (12.4 KiB) Viewed 25 times
@ B/S (m) Remarks 0.666 BM SIOS RL I/S (m) F/S (m) HI (m) (MAMSL) 124.122 123.456 0.570 123.552 0.634 123.488 0.681 123.441 0-000 0.025 0-050 0.710 0-075 0.690 0+100 0.033 123.412 123.432 1.705 122.45 122.417 2.891 119.559 4.596 TP 12 BM S102 M 0.699 B checks EBS - Efs : Last RL- First RL -) 0.699-4.596 = 119.5 59 - 123.456 -3,897 - 3.897 Slope = RL25 - RLX x 100 Xios こ 75-25 123.438-123.412 50 0.152 % Ane U
Question 2 On a graph paper OR drafting software (for example AutoCAD) use appropriate horizontal and vertical scales to produce a longitudinal section of the centre line of the existing road from chainage 0+000 to chainage 0+100 in question 1 above. Plan should have appropriate map components (horizontal and vertical scales, orientation, title) [10 marks
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