Find the center of gravity of the region in the first octant bounded by x+y+z=1

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899604
Joined: Mon Aug 02, 2021 8:13 am

Find the center of gravity of the region in the first octant bounded by x+y+z=1

Post by answerhappygod »

Find the center of gravity of the region in the first octantbounded by x+y+z=1
Find The Center Of Gravity Of The Region In The First Octant Bounded By X Y Z 1 1
Find The Center Of Gravity Of The Region In The First Octant Bounded By X Y Z 1 1 (35.8 KiB) Viewed 19 times
Let G=(xˉ,yˉ​,zˉ) be the center of gravity of an object. The coordinates of the G is given by, xˉ=∭V​ρdV∭V​xρdV​,yˉ​=∭V​ρdV∭V​yρdV​,zˉ=∭V​ρdV∭V​zρdV​ Where, ρ be the mass of unit volume. Find the center of gravity of the region in the first octant bounded by x+y+z=1.
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply