- Find The Solution Of The Given Initial Value Problem Y Y Sec T Y 0 6 Y 0 3 Y 0 4 Y T Tcos T 4cos T 3sin 1 (270.02 KiB) Viewed 33 times
Find the solution of the given initial value problem: y′′′+y′=sec(t),y(0)=6,y′(0)=3,y′′(0)=−4 y(t)=−tcos(t)+4cos(t)+3sin
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Find the solution of the given initial value problem: y′′′+y′=sec(t),y(0)=6,y′(0)=3,y′′(0)=−4 y(t)=−tcos(t)+4cos(t)+3sin
Find the solution of the given initial value problem: y′′′+y′=sec(t),y(0)=6,y′(0)=3,y′′(0)=−4 y(t)=−tcos(t)+4cos(t)+3sin(t)+ln(tan(t)+sec(t))+ln(cos(t))sin(t)+2
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