(h) Let f(t)=sin(4t). Compute f(2001)(t), that is, the 2001 th derivative of f. f′(t)=cos(4t)⋅4 f′′(t)=−sin(4t)⋅42⇒ so y

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answerhappygod
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(h) Let f(t)=sin(4t). Compute f(2001)(t), that is, the 2001 th derivative of f. f′(t)=cos(4t)⋅4 f′′(t)=−sin(4t)⋅42⇒ so y

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H Let F T Sin 4t Compute F 2001 T That Is The 2001 Th Derivative Of F F T Cos 4t 4 F T Sin 4t 42 So Y 1
H Let F T Sin 4t Compute F 2001 T That Is The 2001 Th Derivative Of F F T Cos 4t 4 F T Sin 4t 42 So Y 1 (52.03 KiB) Viewed 39 times
(h) Let f(t)=sin(4t). Compute f(2001)(t), that is, the 2001 th derivative of f. f′(t)=cos(4t)⋅4 f′′(t)=−sin(4t)⋅42⇒ so you see the putteru fmin (t)=sin(4t)⋅44f(t) in sone factor of 4 =f(t)−44  (i) Let x2+y3=4xy, compute dxdy​x(x2+y3)=dxd​4xy​⇒2001/4=500…1⇒f(200i)(t) topes sance frove ​ dy−4y−2x
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