Problem 6.23 (Ans. 17.2 mm) wp = 24 kN/m wl = 16 kN/m 460 mm 530 mm 4 #22 -6 m 300 mm 70 mm Problems in SI Units For P

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Problem 6.23 (Ans. 17.2 mm) wp = 24 kN/m wl = 16 kN/m 460 mm 530 mm 4 #22 -6 m 300 mm 70 mm Problems in SI Units For P

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Problem 6 23 Ans 17 2 Mm Wp 24 Kn M Wl 16 Kn M 460 Mm 530 Mm 4 22 6 M 300 Mm 70 Mm Problems In Si Units For P 1
Problem 6 23 Ans 17 2 Mm Wp 24 Kn M Wl 16 Kn M 460 Mm 530 Mm 4 22 6 M 300 Mm 70 Mm Problems In Si Units For P 1 (19.37 KiB) Viewed 26 times
Problem 6 23 Ans 17 2 Mm Wp 24 Kn M Wl 16 Kn M 460 Mm 530 Mm 4 22 6 M 300 Mm 70 Mm Problems In Si Units For P 2
Problem 6 23 Ans 17 2 Mm Wp 24 Kn M Wl 16 Kn M 460 Mm 530 Mm 4 22 6 M 300 Mm 70 Mm Problems In Si Units For P 2 (17.78 KiB) Viewed 26 times
Problem 6 23 Ans 17 2 Mm Wp 24 Kn M Wl 16 Kn M 460 Mm 530 Mm 4 22 6 M 300 Mm 70 Mm Problems In Si Units For P 3
Problem 6 23 Ans 17 2 Mm Wp 24 Kn M Wl 16 Kn M 460 Mm 530 Mm 4 22 6 M 300 Mm 70 Mm Problems In Si Units For P 3 (17.78 KiB) Viewed 26 times
Problem 6.23 (Ans. 17.2 mm) wp = 24 kN/m wl = 16 kN/m 460 mm 530 mm 4 #22 -6 m 300 mm 70 mm
Problems in SI Units For Problems 6.23 to 6.25, calculate the instantaneous deflections. Use normal weight concrete with = 28 MPa and f, = 420 MP.. Assume that the wo values shown include the beam weights. E. = 200000 MPa. Problem 6.23 (Ans. 17.2 mm) Wp = 24 kN/m we = 16 kN/m 460 mm 530 mm 4 #22 6 m 300 mm 70 mm
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