(a) θ→0lim​θ2sin(4θ)sin(5θ)​​=θ→0lim​θsin(40)​⋅44​⋅θ→0lim​θsin(5θ)​⋅55​=4⋅5=20​

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answerhappygod
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(a) θ→0lim​θ2sin(4θ)sin(5θ)​​=θ→0lim​θsin(40)​⋅44​⋅θ→0lim​θsin(5θ)​⋅55​=4⋅5=20​

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(a) θ→0lim​θ2sin(4θ)sin(5θ)​​=θ→0lim​θsin(40)​⋅44​⋅θ→0lim​θsin(5θ)​⋅55​=4⋅5=20​
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