Given the following thermochemical equation: N₂ (g) + O₂2 NO 02 (g) ΔΗ = + 43.20 kcal N₂ (g) + 3 H₂ (g) → 2 NH3 > (g) 22
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Given the following thermochemical equation: N₂ (g) + O₂2 NO 02 (g) ΔΗ = + 43.20 kcal N₂ (g) + 3 H₂ (g) → 2 NH3 > (g) 22
Given the following thermochemical equation: N₂ (g) + O₂2 NO 02 (g) ΔΗ = + 43.20 kcal N₂ (g) + 3 H₂ (g) → 2 NH3 > (g) 22.10 kcal 2 H₂ (g) + O₂(g) → 2 H₂O (1) AH = - 115.60 kcal ΔΗ = - == Calculate the AH for the following thermochemical equation: 4 NH3(g) + 502 (g) → 4 NO (g) + 6 H₂O (1) Please do not include units in your answer. You must show Hess's Law set-up to get full credit when you upload your work. This means show how the equations add together to get the final equation. You must rewrite each equation. Include proper sig figs in your answer
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