4 HCI (aq) + O2 (aq) = 2 H₂O(g) + 2 Cl₂ (g) Initially 0.574 M HCI, 0.551 M O₂ and 0.407 M H₂O were placed into a contain

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answerhappygod
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4 HCI (aq) + O2 (aq) = 2 H₂O(g) + 2 Cl₂ (g) Initially 0.574 M HCI, 0.551 M O₂ and 0.407 M H₂O were placed into a contain

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4 Hci Aq O2 Aq 2 H O G 2 Cl G Initially 0 574 M Hci 0 551 M O And 0 407 M H O Were Placed Into A Contain 1
4 Hci Aq O2 Aq 2 H O G 2 Cl G Initially 0 574 M Hci 0 551 M O And 0 407 M H O Were Placed Into A Contain 1 (16.26 KiB) Viewed 32 times
4 HCI (aq) + O2 (aq) = 2 H₂O(g) + 2 Cl₂ (g) Initially 0.574 M HCI, 0.551 M O₂ and 0.407 M H₂O were placed into a container. When the reaction reached equilibrium, there was 0.441 M O2. What is the equilibrium constant Ke for this reaction?
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