Using our data to represent these values K = rate constant E = activation energy A = a constant that represents the like

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Using Our Data To Represent These Values K Rate Constant E Activation Energy A A Constant That Represents The Like 1 (137.5 KiB) Viewed 29 times

Using our data to represent these values K = rate constant E = activation energy A = a constant that represents the likelihood that collisions with the proper orientation occurs R = gas constant (8.314 Jmol-¹K-¹) T = temperature in Kelvin. Experiment 2 4 When we take natural logs of both sides of the equation (natural because we have 'e' in the expression) we find our expression becomes a linear equation. In k = ln A - Ea Ea RT or lnk= Fax +In A This is the equation of a straight line R T mx + C y = If we plot a graph of of In k against 1/T, then we should have a straight line of gradient -E₂/R, and a y intercept of In A. 6. Using experiments 2, 4 and 5, complete the following table of values. 5 temperature °℃ 17 3 32 number of molecular collisions per second temperature, T (K) -Ea k=A-e RT 290 276 305 1/T 3.448x10-3 3.6x10-3 3.279x10-3 number of molecular collisions per second with proper orientation time, t (s) The activation energy for this reaction was calculated to be. kJmol-¹ 110 probability of successful collisions 214 17.5 In (1/1) 7. Plot a graph of these results. Draw a line of best fit through the graph. Determine the gradient of the graph. Calculate E, the activation energy of the reaction. (Send your graph and your calculations either embedded in your report or as an appendix) [3] -4.7 -5.366 -2.862 We are using In(1/t) to represent the rate here. We could use In(1/rate) or In(1/k) the graphs would have the same gradient.