Now, we can use this if the probabilities were not the same (that is 50% - 50%). For instance what if we were looking at

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answerhappygod
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Now, we can use this if the probabilities were not the same (that is 50% - 50%). For instance what if we were looking at

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Now We Can Use This If The Probabilities Were Not The Same That Is 50 50 For Instance What If We Were Looking At 1
Now We Can Use This If The Probabilities Were Not The Same That Is 50 50 For Instance What If We Were Looking At 1 (53.36 KiB) Viewed 32 times
Now We Can Use This If The Probabilities Were Not The Same That Is 50 50 For Instance What If We Were Looking At 2
Now We Can Use This If The Probabilities Were Not The Same That Is 50 50 For Instance What If We Were Looking At 2 (20.85 KiB) Viewed 32 times
Now, we can use this if the probabilities were not the same (that is 50% - 50%). For instance what if we were looking at Steve Nash's free throw shooting percentage of 90.4%. So we could fill in each left-hand bracket with 0.904 for a success and each right hand bracket with 0.096 for a failure. (1.000- 0.904 = 0.096). so therefore if he took 4 free throws our probabilities would look like this: 1 (0.904)*x (0.096) 4 (0.904) x (0.096) 6 (0.904) x (0.096) 4 (0.904) x (0.096) 1 (0.904) x (0,096) So to work out 3 successes and one failure I would look for the term where the exponents were "3" and "1" which gives me: 4 (0.904)³ x (0.096)' which equals: 0.283685 or 28.37% of the time. If I worked out all of the possible terms, they would add up to 1. Also note, that I do not need to write the "row total" underneath the probabilities already have taken that into account. Also note that all of the numbers in Pascal's triangles are a combination number, so the fourth row has five terms each worked out by: 4Co = 1, 4C1 = 4, 4C2 = 6, 4C3 = 4, and 4C4 = 1 Exercise 4 Use the 10th row and Steve Nash's probabilities given above (success equals 0.904 failures equal 0.096). To answer the following questions: Show working in the space provided. Please show working. (1) What is the probability that Nash makes all 10 free throws? (2) What is the probability that Nash misses all 10 free throws?

(3) What is the probability that Nash makes at least 8 free throws? (4) What is the probability that Nash makes at most 9 free throws? This has been a closer look at Pascal's triangle. I urge you to study this a bit more online to see other patterns that may emerge such as the triangular numbers, Fibonacci series, the tetrahedral numbers and the pentatope numbers, etc. This ends this project.
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