Let f(t,y) = ty2. Show that for any c < d, the function f is Lipschitz in y on Ω = [−1,1]×[c,d].
I'm confused to as of why the constant is 2
Let f(t,y) = ty2. Show that for any c < d, the function f is Lipschitz in y on Ω = [−1,1]×[c,d]. I'm confused to as of w
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Let f(t,y) = ty2. Show that for any c < d, the function f is Lipschitz in y on Ω = [−1,1]×[c,d]. I'm confused to as of w
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