Find the equation for the plane through Po(-3,1,2) perpendicular to the following line. x = -3 +t, y = 1 + 5t, z=2t, -∞<

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answerhappygod
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Find the equation for the plane through Po(-3,1,2) perpendicular to the following line. x = -3 +t, y = 1 + 5t, z=2t, -∞<

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Find The Equation For The Plane Through Po 3 1 2 Perpendicular To The Following Line X 3 T Y 1 5t Z 2t 1
Find The Equation For The Plane Through Po 3 1 2 Perpendicular To The Following Line X 3 T Y 1 5t Z 2t 1 (5.96 KiB) Viewed 17 times
Find the equation for the plane through Po(-3,1,2) perpendicular to the following line. x = -3 +t, y = 1 + 5t, z=2t, -∞<t<∞ Using a coefficient of 1 for x, the equation of the plane is
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