Inadequate nutrition is a significant risk factor for low bone density. Kuroda, Onoe, Yoshikata, and Ohta (2013) examine

Business, Finance, Economics, Accounting, Operations Management, Computer Science, Electrical Engineering, Mechanical Engineering, Civil Engineering, Chemical Engineering, Algebra, Precalculus, Statistics and Probabilty, Advanced Math, Physics, Chemistry, Biology, Nursing, Psychology, Certifications, Tests, Prep, and more.
Post Reply
answerhappygod
Site Admin
Posts: 899604
Joined: Mon Aug 02, 2021 8:13 am

Inadequate nutrition is a significant risk factor for low bone density. Kuroda, Onoe, Yoshikata, and Ohta (2013) examine

Post by answerhappygod »

Inadequate Nutrition Is A Significant Risk Factor For Low Bone Density Kuroda Onoe Yoshikata And Ohta 2013 Examine 1
Inadequate Nutrition Is A Significant Risk Factor For Low Bone Density Kuroda Onoe Yoshikata And Ohta 2013 Examine 1 (61.84 KiB) Viewed 30 times
Inadequate Nutrition Is A Significant Risk Factor For Low Bone Density Kuroda Onoe Yoshikata And Ohta 2013 Examine 2
Inadequate Nutrition Is A Significant Risk Factor For Low Bone Density Kuroda Onoe Yoshikata And Ohta 2013 Examine 2 (47.19 KiB) Viewed 30 times
Inadequate Nutrition Is A Significant Risk Factor For Low Bone Density Kuroda Onoe Yoshikata And Ohta 2013 Examine 3
Inadequate Nutrition Is A Significant Risk Factor For Low Bone Density Kuroda Onoe Yoshikata And Ohta 2013 Examine 3 (53.21 KiB) Viewed 30 times
Inadequate nutrition is a significant risk factor for low bone density. Kuroda, Onoe, Yoshikata, and Ohta (2013) examined the nutrition and eating habits of 24 Japanese women, aged 19-25. Participants completed the Diet History Questionnaire, which asked about their eating habits and how many times per month they skipped each major meal. The researchers also took a. number of anthropometric measurements, including lower total hip bone density (LTH-BD) on a scale from 1-20. One of their goals - and what we'll focus on here - was to be able to predict LIH-BD based on the number of times women skip breakfast per month. (1) Choose the appropriate statistical test. ( 13 pts.) (2) Choose a one-tailed or two-tailed test, if appropriate. ( 12 pts.) do One-tailed is Two-tailed Not appropriate (4) Determine the critical value for the test statistic. ( /1pt ) (5) Determine the observed value for the test statistic. ( /1pt ) The computer printouts you need to answer this question are after Step 7. (6) Decide. ( /2 pts.) □ Reiect the null hypothesis □ Fail toreiect the null hyoothesis
Inadequate nutrition is a significant risk factor for low bone density, Kuroda, Onos, Yoshileata, and Ohta (2013) examined the nutrition and eating habits of 24 Japanese women, aged 19-25. Rarticipants completed the Diet History Questionnaire, which asked about their eating habits and how many times per month they skipped each major meal. The researchers also took a. number of anthropometric measurements, including lower total hip bone density (LIH-BD) on a scale from 1-20. One of their goals - and what we'll focus on here - was to be able to predict LTH-BD based on the number of times women skip breakfast per month. (3) State the hypotheses. ( 16pts.) (i) Write a conclusion (a) describing the research results in the context o ? Copy \& paste it of the research, then (b) generalizing to the population, stating what you leamed about the relationship between the variables. ( /,10pts )
Next, using the "standard form" of the regression equation, insert into the equation the appropriate numbers from the SPSS printout (above). ( /1pt ) Standard form: γ=a+bx Your equation: Now choose one value for the independent variable - from the partial data set below − and use "Your equation" to predict the value of the dependent variable by doing the arithmetic. Finally, compare your predicted value (M) to the actual value (Y) for the dependent variable. The actual value comes from the data set. ( /1pt ) Your calculations to predict the value of the dependent variable below: The predicted value of the dependent variable, from above: yn​= The actual value of the dependent variable, from the data set: Y= In words, and very briefly, how good do you think the prediction is?
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!
Post Reply