Consider A Multinomial Experiment With N 280 And K 3 The Null Hypothesis Is Ho P1 0 40 P2 0 40 And P3 0 20 1 (101.25 KiB) Viewed 51 times
Consider a multinomial experiment with n = 280 and k = 3. The null hypothesis is Ho: p1 0.40, P2 = 0.40, and p3 = 0.20. The observed frequencies resulting from the experiment are: (You may find it useful to reference the appropriate table: chi-square table or Ftable) Category Frequency a. Choose the appropriate alternative hypothesis. 1 2 120 110 3 50 All population proportions differ from their hypothesized values. O At least one of the population proportions differs from its hypothesized value. Test statistic = b-1. Calculate the value of the test statistic. (Round intermediate calculations to at least 4 decimal places and final answer to 3 decimal places.)
b-2. Find the p-value. p-value > 0.10 0.05 ≤ p-value < 0.10 0.025 ≤ p-value < 0.05 0.01 ≤ p-value < 0.025 p-value < 0.01 c. At the 10% significance level, what is the conclusion to the hypothesis test? Do not reject Ho since the p-value is more than significance level. Reject Ho since the p-value is less than significance level. Do not reject Ho since the p-value is less than significance level. Reject Ho since the p-value is more than significance level.
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