- A C6x13 A36 Steel Purlins Spaced 0 90 M O C With 20 Mm Diameter Sagrods Tierods Midpoint Is Subjected To The 1 (42.19 KiB) Viewed 34 times
- A C6x13 A36 Steel Purlins Spaced 0 90 M O C With 20 Mm Diameter Sagrods Tierods Midpoint Is Subjected To The 2 (42.19 KiB) Viewed 34 times
- A C6x13 A36 Steel Purlins Spaced 0 90 M O C With 20 Mm Diameter Sagrods Tierods Midpoint Is Subjected To The 3 (31.47 KiB) Viewed 34 times
Problem 2. In Problem 1, the truss made of L100x100x10 A36 Steel Angle is subjectedto vertical load @D (to be multiplied by 7 based on the last digit of student no). Use Fy= 250MPA
Required: Check the adequacy of the truss members by using LRFD-NSCP 2010 & fortension members, use M=wL2/11
A C6x13 A36 Steel Purlins spaced @ 0.90 m. o. c. with 20 mm. diameter. Sagrods & Tierods @ midpoint is subjected to the following roof loads: D=2.0 KPa, Lr=0.5 KPa, & V=250 KPH (wind velocity). Use Fy=250 MPA &fs=150 MPa, Lb=5.0 m. o. c. (spacing of truss) Required: Check the adequacy of the following using LRFD- NSCP 2010 & MRM: (1)C6x13 A36 Steel Purlins; (2) 16 mm. diameter Sagrods & Tierods. 4.0 m B Dh 20 KN 4.0 m 5.0 m Oak
given 18=15-44² self weight of purlin. = 3.38 kg/m • SS-5 N/m. Give (oad = (0.60) purlin spacing. = 0·60 x 0-80-418 KM snow load = 0.86x 0.96 = 0.798 KN (Normal to roof) ME Weight of Roofing = 0·12x spacing = 0·1650-8 = 0.12. Total load = (0-0535 + 0-48+0-12) KN 653-5 N/m. component of load parallel to roofing. = 635-5 sin 15.94. = 175.98 N/m. 9 = tan¹ (3) = 15.04. sag oods are placed at mid points => fall = 173.98 x 6 = 521.94 N. As per LRFD; Tan = 1'5x full = 1·5X52184 = 782-90 N. Required net are = Tan 0.33 Fu The Tods b/w ridge partine. sunce provide 16 mm dla sag rode kafth threaded ara of 157 mm² between purlins. TR2-9 0.33 X480 Pall in the rods 4x 521.94x see 15.94 as per LRFD; Tan= 11t* full Required area; = Tan = 2171.24 N. = 5.93mm- =1*2111-24 = 3257N. 8.53 fu 3467 D-33XORD = 24-67mm2² Mence, provide 16 mm dia tie roos blu ridge purling.